ਫਰਮਾ:Math/notstyles

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Escaping symbols

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basic

${z : ℐ m z > 0 } and u (t) = ℛ e f (t + 0\cdot i), then ℐ m f (t + 0\cdot i) = H (u)(t)$

The =-sign

${{{1}}}$

$1+2=3$

Using unnamed parameter 1

${{{1}}}$

$1+2=3$

The |-sign (pipe)

$a abs:$

$a abs: | a |$

blank positional

$a abs:$

using {{!}}

$a abs: | a | is a abs |$

Times New Roman (current template)

(font-family: 'Times New Roman', 'Nimbus Roman No9 L', Times, serif;)

A compact way of rephrasing the point that the base- $b$ logarithm of $y$ is the solution $x$ to the equation $f (x) = b x = y$ is to say that the logarithm function is the inverse function of the exponential function. Inverse functions are closely related to the original functions: the graphs of the two correspond to each other upon reflecting them at the diagonal line $x = y$ , as shown at the right: a point $(t, u = b t)$ on the graph of the exponential function yields a point $(u, t = log b u)$ on the graph of the logarithm and vice versa. Moreover, analytic properties of the function pass to its inverse function. Thus, as the exponential function $f (x) = b x$ is continuous and differentiable, so is its inverse function, $log b (x)$ . Roughly speaking, a differentiable function is one whose graph has no sharp "corners".